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महाराष्ट्र राज्य शिक्षण मंडळएस.एस.सी (इंग्रजी माध्यम) इयत्ता १० वी

The Ratio of the Areas of Two Triangles with the Common Base is 4 : 3. Height of the Larger Triangle is 2 Cm, Then Find the Corresponding Height of the Smaller Triangle. - Geometry Mathematics 2

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प्रश्न

The ratio of the areas of two triangles with the common base is 4 : 3. Height of the larger triangle is 2 cm, then find the corresponding height of the smaller triangle.

बेरीज

उत्तर

Let the height of the larger triangle be h1 and that of the smaller triangle be h2.

The ratio of the areas of two triangles with a common base is equal to the ratio of their corresponding heights.

`"Area(larger Triangle)"/"Area(smaller Triangle)"="h"_1/"h"_2`

`4/3=2/"h"_2`

`4xx "h"_2=3xx2`

`therefore"h"_2=(3xx2)/4=6/4`

`therefore"h"_2=1.5" cm"`

The corresponding height of the smaller triangle is 1.5 cm.

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2014-2015 (March) Set A

संबंधित प्रश्‍न

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In the figure, PM = 10 cm, A(∆PQS) = 100 sq.cm, A(∆QRS) = 110 sq. cm, then find NR.


In ∆ABC, B – D – C and BD = 7, BC = 20 then Find following ratio. 

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if BE = 6 and AD = 9 find `(A(Δ ABE))/(A(Δ BAD))`.


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In ΔABC, B − D − C and BD = 7, BC = 20, then find the following ratio.

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