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Two Submarines Are Approaching Each Other in a Calm Sea. the First Submarine Travels at a Speed of 36 Km H−1 and the Other at 54 Km H−1 Relative to the Water. - Physics

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प्रश्न

Two submarines are approaching each other in a calm sea. The first submarine travels at a speed of 36 km h−1 and the other at 54 km h−1 relative to the water. The first submarine sends a sound signal (sound waves in water are also called sonar) at a frequency of 2000 Hz. (a) At what frequency is this signal received from the second submarine. At what frequency is this signal received by the first submarine. Take the speed of of the sound wave in water to be 1500 m s−1.

बेरीज

उत्तर

Given:
Velocity of water v = 1500 m/s
Frequency of sound signal \[f_0\]= 2000 Hz
Velocity of first submarine vs = 36 kmh−1 = \[36 \times \frac{5}{18} \text{ m/s }\]

Velocity of second submarine \[v_0\]= 54 km h−1  = \[54 \times \frac{5}{18}\] m/s = 15 m/s
Frequency received by the first submarine \[\left( f_1 \right)\] is given by:

\[f_1    = \left( \frac{v  + v_0}{v  - v_s} \right) f_0\]

On substituting the values, we get:

\[f_1    = \left( \frac{1500 + 15}{1500 - 10} \right) \times (2000)\] 

\[         =   2034  \text { Hz }\]

(b) Here, 

\[f_0    =   2034  Hz\]

Apparent frequency received by second submarine \[\left( f_2 \right)\] is given by :

\[f_2    = \left( \frac{1500 + 10}{1500 - 15} \right) \times (2034)\] 

\[       = 2068  \text { Hz }\]

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Speed of Wave Motion
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पाठ 16: Sound Waves - Exercise [पृष्ठ ३५७]

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एचसी वर्मा Concepts of Physics Vol. 1 [English] Class 11 and 12
पाठ 16 Sound Waves
Exercise | Q 76 | पृष्ठ ३५७

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