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Question
A ladder 10m long reaches the window of a house 8m above the ground. Find the distance of the foot of the ladder from the base of the wall.
Solution
Let AB be A ladder and B is the window at 8 m above the ground C.
Now, In right triangle ABC
By using Pythagoras theorem, we have
`AB^2=BC^2+CA^2`
⇒ `10^2=8^2+CA^2`
⇒ `CA^2=100-64`
⇒ `CA^2=36`
⇒` CA=6m`
Hence, the distance of the foot of the ladder from the base of the wall is 6 m.
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