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Question
A ladder 17 m long reaches a window of a building 15 m above the ground. Find the distance of the foot of the ladder from the building.
Solution
In ΔABC, by Pythagoras theorem
AB2 + BC2 = AC2
⇒ 152 + BC2 = 172
⇒ 225 + BC2 = 289
⇒ BC2 = 289 − 225
⇒ BC2 = 64
⇒ BC = 8 m
∴ Distance of the foot of the ladder from building = 8 m
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