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Question
A ladder is placed along a wall of a house such that its upper end is touching the top of the wall. The foot of the ladder is 2 m away from the wall and the ladder is making an angle of 60° with the level of the ground. Determine the height of the wall.
Solution
Let AB be the wall of height, hm and C be the points, makes an angle 60° and foot of the ladder is 2m away from the wall. We have to find the height of the wall
In a triangle ABC, given that BC = 2m and angle C = 60°
Now we have to find the height of the wall.
So we use trigonometrically ratios.
In a triangle ABC
`=> tan C = (AB)/(BC)`
`=> tan 60^@ = h/2`
`=> sqrt3 = h/2`
`=> h = 2sqrt3`
Hence height of wall is `2sqrt3` meters
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