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Question
A lady plans to save for her daughter’s marriage. She wishes to accumulate a sum of ₹4,64,100 at the end of 4 years. What amount should she invest every year if she gets an interest of 10% p.a. compounded annually? [Given (1.1)4 = 1.4641]
Solution
Given, A = ₹4,64,100, n = 4 years, r = 10% p.a.
i = `"r"/(100) = (10)/(100)` = 0.1
Now, A = `"C"/"i"[(1 + "i")^"n" - 1]`
∴ 4,64,100 = `"C"/(0.1)[(1 + 0.1)^4 - 1]`
∴ 4,64,100(0.1) C[(1.1)4 – 1]
∴ 46,410 = C[1.4641 – 1]
∴ 46,410 = C(0.4641)
∴ C = `(46,410)/(0.4641)`
∴ C = 1,00,000
∴ She must invest ₹1,00,000 every year.
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