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Question
A pole casts a shadow of length \[2\sqrt{3}\] m on the ground, when the sun's elevation is 60°. Find the height of the pole.
Solution
Let AB be the height of the pole and BC be the shadow of the pole.
Given:
BC =\[2\sqrt{3}\]
In ∆ABC,
\[\tan60^o = \frac{AB}{BC}\]
\[ \Rightarrow \sqrt{3} = \frac{AB}{2\sqrt{3}}\]
\[ \Rightarrow AB = 6 m\]
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