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Question
A side of an isosceles right angled triangle is x. Find its hypotenuse.
Solution
It is given that, a side of an isosceles right-angled triangle is x.
Then, the other side of the triangle is also x.
According to Pythagoras theorem.
\[\left( \text{Hypotenuse} \right)^2 = x^2 + x ^2 \]
\[ = 2 x^2 \]
\[ \therefore \text{Hypotenuse} = x\sqrt{2}\]
Hence, its hypotenuse is x\[\sqrt{2}\]
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