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Question
A uniform electric field of 10 N C−1 exists in the vertically downward direction. Find the increase in the electric potential as one goes up through a height of 50 cm.
Solution
Electric field intensity, E = 10 N/C,
Change in height, ds = 50 cm = `1/2`m
Change in electric potential, dV = E.ds = 10 × `1/2= 5` V
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