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Question
ΔABC ~ ΔPQR, A(ΔABC) = 80 sq.cm, A(ΔPQR) = 125 sq.cm, then complete `("A"(Δ"ABC"))/("A"(Δ"PQR")) = 80/125 = (["______"])/(["______"])`, hence `"AB"/"PQ" = (["______"])/(["______"])`
Solution
`("A"(Δ"ABC"))/("A"(Δ"PQR")) = 80/125` = `16/25` ......(i)[Given]
`("A"(Δ"ABC"))/("A"(Δ"PQR")) = "AB"^2/"PQ"^2` .....(ii)[Theorem of areas of similar triangles]
∴ `"AB"^2/"PQ"^2 = 16/25` .....[From (i) and (ii)]
Hence `"AB"/"PQ"` = `4/5` ......[[Taking square root of both sides]
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