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Question
In fig., PM = 10 cm, A(ΔPQS) = 100 sq.cm, A(ΔQRS) = 110 sq.cm, then NR?
ΔPQS and ΔQRS having seg QS common base.
Areas of two triangles whose base is common are in proportion of their corresponding [______]
`("A"("PQS"))/("A"("QRS")) = (["______"])/"NR"`,
`100/110 = (["______"])/"NR"`,
NR = [ ______ ] cm
Solution
ΔPQS and ΔQRS having seg QS common base.
Areas of two triangles whose base is common are in proportion of their corresponding heights.
`("A"("ΔPQS"))/("A"("ΔQRS"))` = `"PM"/"NR"`,
`100/110` = `10/"NR"`,
∴ NR = `(110 xx 10)/100`
∴ NR = 11 cm.
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