English

Consider structures I to VII and answer the question: I. CH3 – CH2 – CH2 – CH2 – OH II. CHX3−CHX2−CH−CHX3.....|.......OH III. ...CHX3|CHX3−C−CHX3|..OH IV. CHX3−CH−CHX2−OH|........CHX3...... - Chemistry

Advertisements
Advertisements

Question

Consider structures I to VII and answer the question:

I. CH3 – CH2 – CH2 – CH2 – OH
II. \[\begin{array}{cc}
\ce{CH3 - CH2 - CH - CH3}\\
\phantom{.....}|\\
\phantom{.......}\ce{OH}
\end{array}\]
III. \[\begin{array}{cc}
\phantom{...}\ce{CH3}\\
\phantom{}|\\
\ce{CH3 - C - CH3}\\
\phantom{}|\\
\phantom{..}\ce{OH}
\end{array}\]
IV. \[\begin{array}{cc}
\ce{CH3 - CH - CH2 - OH}\\
|\phantom{........}\\
\ce{CH3}\phantom{......}
\end{array}\]
V. CH3 – CH2 – O – CH2 – CH3
VI. CH3 – O – CH2 – CH2 – CH3
VII. \[\begin{array}{cc}
\ce{CH3 - O - CH - CH3}\\
\phantom{...}|\\
\phantom{......}\ce{CH3}
\end{array}\]

Identify the pairs of compounds that represents chain isomerism.

Short Note

Solution

If two or more compounds have the same molecular formula but different carbon skeletons then these compounds are referred to as chain isomers and the phenomenon is termed as chain isomerism. The pairs of compounds that represent chain isomerism are- I, II, III, IV.

shaalaa.com
Isomerism
  Is there an error in this question or solution?
Chapter 12: Organic Chemistry Some Basic Principles and Techniques - Multiple Choice Questions (Type - I) [Page 150]

APPEARS IN

NCERT Exemplar Chemistry [English] Class 11
Chapter 12 Organic Chemistry Some Basic Principles and Techniques
Multiple Choice Questions (Type - I) | Q 26 | Page 150

RELATED QUESTIONS

Write IUPAC name of the product obtained by the ozonolysis of the following compound:

3,4-Dimethyl-hept-3-ene


Draw the cis and trans structures of hex-2-ene. Which isomer will have higher b.p. and why?


What effect does branching of an alkane chain has on its boiling point?


What is the relationship between the members of following pairs of structures? Are they structural or geometrical isomers or resonance contributors?


In which of the following, functional group isomerism is not possible?


Which of the following pairs are position isomers?

I. \[\begin{array}{cc}
\phantom{.......................}\ce{O}\\
\phantom{.......................}||\\
\ce{CH3 - CH2 - CH2 - CH2 - C - H}
\end{array}\]
II. \[\begin{array}{cc}
\phantom{.................}\ce{O}\\
\phantom{.................}||\\
\ce{CH3 - CH2 - CH2 - C - H}
\end{array}\]
III. \[\begin{array}{cc}
\ce{CH3 - CH2 - C - CH2 - CH3}\\
\phantom{}||\\
\phantom{}\ce{O}
\end{array}\]
IV. \[\begin{array}{cc}
\ce{CH3 - CH - CH2 - C - H}\\
\phantom{...}|\phantom{............}||\phantom{}\\
\phantom{...}\ce{CH3}\phantom{.........}\ce{O}\phantom{}
\end{array}\]

(i) I and II

(ii) II and III

(iii) II and IV

(iv) III and IV


Which of the following pairs are not functional group isomers?

I. \[\begin{array}{cc}
\phantom{.......................}\ce{O}\\
\phantom{.......................}||\\
\ce{CH3 - CH2 - CH2 - CH2 - C - H}
\end{array}\]
II. \[\begin{array}{cc}
\phantom{.................}\ce{O}\\
\phantom{.................}||\\
\ce{CH3 - CH2 - CH2 - C - H}
\end{array}\]
III. \[\begin{array}{cc}
\ce{CH3 - CH2 - C - CH2 - CH3}\\
\phantom{}||\\
\phantom{}\ce{O}
\end{array}\]
IV. \[\begin{array}{cc}
\ce{CH3 - CH - CH2 - C - H}\\
\phantom{...}|\phantom{............}||\phantom{}\\
\phantom{...}\ce{CH3}\phantom{.........}\ce{O}\phantom{}
\end{array}\]

(i) II and III

(ii) II and IV

(iii) I and IV

(iv) I and II


Consider structures I to VII and answer the question:

I. CH3 – CH2 – CH2 – CH2 – OH
II. \[\begin{array}{cc}
\ce{CH3 - CH2 - CH - CH3}\\
\phantom{.....}|\\
\phantom{.......}\ce{OH}
\end{array}\]
III. \[\begin{array}{cc}
\phantom{...}\ce{CH3}\\
\phantom{}|\\
\ce{CH3 - C - CH3}\\
\phantom{}|\\
\phantom{..}\ce{OH}
\end{array}\]
IV. \[\begin{array}{cc}
\ce{CH3 - CH - CH2 - OH}\\
|\phantom{........}\\
\ce{CH3}\phantom{......}
\end{array}\]
V. CH3 – CH2 – O – CH2 – CH3
VI. CH3 – O – CH2 – CH2 – CH3
VII. \[\begin{array}{cc}
\ce{CH3 - O - CH - CH3}\\
\phantom{...}|\\
\phantom{......}\ce{CH3}
\end{array}\]

Identify the pairs of compounds which are functional group isomers.


Assertion (A): Pent- 1- ene and pent- 2- ene are position isomers.

Reason (R): Position isomers differ in the position of functional group or a substituent.


Tautomerism is exhibited by ______. 


The compound which shows metamerism is ______


Which type of isomerism can not be shown by benzaldoxime?


The correct stereochemical name of


How many structural isomers possible of the molecular formula C3H6O (excluding enol form)?


The number of acyclic structural isomers (including geometrical isomers) for pentene are ______.


Which of the following reactions will not produce a racemic product?


The total number of possible isomers of the complex compound [CuII(NH3)4][PtIICl4] is ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×