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Evaluate: 2 Tan 57 ° Cot 33 ° − Cot 70 ° Tan 20 ° − √ 2 Cos 45 ° - Mathematics

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Question

Evaluate: `2(tan57°)/(cot33°) - (cot70°)/(tan20°) - sqrt(2) cos 45°`

Sum

Solution

`2(tan57°)/(cot33°) - (cot70°)/(tan20°) - sqrt(2) cos 45°`

= `2(tan(90° - 33°))/(cot33°) - (cot(90° - 20°))/(tan20°) - sqrt(2) (1/sqrt(2))`

= `2(cot33°)/(cot33°) - (tan20°)/(tan20°) - 1`

= 2 - 1 - 1

= 0.

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Chapter 25: Complementary Angles - Exercise 25 [Page 310]

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Selina Concise Mathematics [English] Class 9 ICSE
Chapter 25 Complementary Angles
Exercise 25 | Q 6.6 | Page 310
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