मराठी

Evaluate: 2 Tan 57 ° Cot 33 ° − Cot 70 ° Tan 20 ° − √ 2 Cos 45 ° - Mathematics

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प्रश्न

Evaluate: `2(tan57°)/(cot33°) - (cot70°)/(tan20°) - sqrt(2) cos 45°`

बेरीज

उत्तर

`2(tan57°)/(cot33°) - (cot70°)/(tan20°) - sqrt(2) cos 45°`

= `2(tan(90° - 33°))/(cot33°) - (cot(90° - 20°))/(tan20°) - sqrt(2) (1/sqrt(2))`

= `2(cot33°)/(cot33°) - (tan20°)/(tan20°) - 1`

= 2 - 1 - 1

= 0.

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पाठ 25: Complementary Angles - Exercise 25 [पृष्ठ ३१०]

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सेलिना Concise Mathematics [English] Class 9 ICSE
पाठ 25 Complementary Angles
Exercise 25 | Q 6.6 | पृष्ठ ३१०
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