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Question
`(sin 75^circ)/(cos 15^circ)` = ?
Solution
`(sin 75^circ)/(cos 15^circ)` = `(sin(90^circ - 15^circ))/(cos 15^circ)`
= `(cos 15^circ)/(cos 15^circ)` .....[∵ sin(90° – θ) = cos θ]
= 1
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