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Question
Evaluate the following
`sec 11^@/(cosec 79^@)`
Solution
Given that `sec 11^@/(cosec 79^@)`
Since `sec(90 - theta) = cosec theta`
`=> sec 11/(cosec 79) = (sec (90 - 79))/(cosec 79)`
`=> sec 11/(cosec 79) = (cosec 79)/(cosec 79)`
`=> sec 11/(cosec 79) = 1`
Therefore `sec 11/(cosec 79) = 1`
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