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Question
`f(x)=(x^2-9)/(x - 3)` is not defined at x = 3. what value should be assigned to f(3) for continuity of f(x) at = 3?
Solution
To be continuous at x = 3'
`f(3)=lim_(x -> 3) (x^2 - 9)/(x-3)`
`=lim_(x->3)((x-3)(x + 3))/(x-3)`
`= lim_(x->3)(x + 3) = 6`
f(3)=6
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