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Question
Find the area and perimeter of the following sector :
Radius= 6 cm, angle at the centre is 70°
Solution
Area of the sector = `pi "r"^2 xx theta/360^circ`
`= 22/7 xx 6 xx 6 xx 70^circ/360^circ`
= 22 cm2
Perimeter of the sector = `2"r" + (2 pi "r" xx theta/360^circ)`
`= 2 xx 6 + (2 xx 22/7 xx 6 xx 70^circ/360^circ)`
= 12 + 7.33
= 19.33 cm
Area of the sector = 22 cm2 and perimeter = 19. 33 cm
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