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Question
Find the area of a triangle whose vertices are
(6,3), (-3,5) and (4,2)
Solution
We know area of triangle formed by three points (x1y1) , (x2y2), and (x3y3)is given by `triangle=1/2 [x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)]`
The vertices are given as (6, 3), (−3, 5), (4, −2).
`triangle=1/2[6(5+2)-3(-2-3)+4(3-5)]`
`=1/2 [6xx7-3xx(-5)+4xx(-2)]`
`=1/2[42+15-8]`
`49/2 `sq units
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