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Karnataka Board PUCPUC Science Class 11

Find the Equivalent Resistances of the Networks Shown in the Figure Between the Points A And B. - Physics

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Question

Find the equivalent resistances of the networks shown in the figure between the points a and b.

Sum

Solution

(a) The circuit can be simplified stepwise, as shown below.

The effective resistance between the points a and b,

\[R_{eff} = \frac{\frac{5r}{3} \times r}{\frac{5r}{3} + r} = \frac{5r}{8}\]

(b) The circuit can be simplified, as shown below.

The effective resistance between the points a and b,

\[R_{eff} = \left( \frac{r}{3} \right) + r = \frac{4r}{3}\]

(c)

From the figure, it can be seen that axbya is a balanced Wheatstone bridge. The resistors in branch xy will, thus, become ineffective. The circuit can be simplified as under

The effective resistance between the points a and b,

\[R_{eff} = \left( \frac{2r \times 2r}{2r + 2r} \right) = r\]

(d) The circuit can be simplified as shown below.

The effective resistance between the points a and b,

\[R_{eff} = \frac{r}{4}\]

(e) The circuit can be redrawn as shown below.

Now, we can see that the circuit is a balanced Wheatstone bridge. So, the branch xy will become ineffective. Thus, the simplified circuit will become as shown below.

The effective resistance between the points a and b,

\[R_{eff} = \left( \frac{2r \times 2r}{2r + 2r} \right) = r\]

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Chapter 10: Electric Current in Conductors - Exercises [Page 201]

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HC Verma Concepts of Physics Vol. 2 [English] Class 11 and 12
Chapter 10 Electric Current in Conductors
Exercises | Q 45 | Page 201

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