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Question
Find the equation of the line containing point A(3, 5) and having slope `2/3`.
Solution
Given, slope(m) = `2/3` and the line passes through (3, 5).
Equation of the line in slope point form is y – y1 = m(x – x1)
∴ The equation of the required line is
y – 5 = `2/3("x" - 3)`
∴ 3(y – 5) = 2(x – 3)
∴ 3y – 15 = 2x – 6
∴ 2x – 3y + 9 = 0
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