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Question
Find the equation of the line containing point A(4, 3) and having inclination 120°
Solution
Given, Inclination of line = θ = 120°
∴ Slope of the line (m) = tan θ
= tan 120°
= tan (90° + 30°)
= – cot 30°
= `-sqrt(3)`
and the line passes through A(4, 3).
Equation of the line in slope point form is
y – y1 = m(x – x1)
∴ The equation of the required line is
y – 3 = `-sqrt(3)("x" - 4)`
∴ y – 3 = `-sqrt(3) "x" + 4sqrt(3)`
∴ `sqrt(3) "x" + "y" - 3 - 4sqrt(3)` = 0
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