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Question
Find the value of x if `[(3x + y, -y),(2y - x, 3)] = [(1, 2),(-5, 3)]`
Solution
`[(3x + y, -y),(2y - x, 3)] = [(1, 2),(-5, 3)]`
Comparing the corresponding terms, we get.
-y = 2
⇒ y = -2
3x + y = 1
⇒ 3x = 1 – y
⇒ 3x = 1 – (–2)
= 1 + 2
= 3
⇒ x = `(3)/(3)`
= 1
Hence x = 1, y = –2.
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