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Question
Four equal circles each of radius a, touch each other. Show that area between them is `6/7a^2`
Solution
Let circles be with centres A, B, C, D]
Join A, B, C and D then ABCD is square formed with side = (a + a) = 2a
Radius = a
Area between circles = area of square – 4(area of quadrant)
(shaded region)
= (2๐)2 − 4 (`1/4`๐๐๐๐ ๐๐ ๐๐๐๐๐๐ ๐ค๐๐กโ ๐๐๐๐๐ข๐ ′๐′)
=` 4a^2 − 4 (1/4) × a^2`
= ๐2(4 − ๐)
= ๐2 (4 −`22/7`)
= `((28−22)/7) a^2 =6/7a^2`
∴ Area between circles =`6/7a^2.`
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