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Question
If 8tanA = 15, find sinA - cosA.
Solution
8tanA = 15
⇒ tanA = `(15)/(8) = "Perpendicular"/"Base"`
Hypotenuse
= `sqrt(("Perpendicular")^2 + ("Base")^2`
= `sqrt((15)^2 + (8)2`
= `sqrt(225 + 64)`
= `sqrt(289)`
= 17
sinA - cosA = `"Perpendicular"/"Hypotenuse" - "Base"/"Hypotenuse"`
= `(15)/(17) - (8)/(17)`
= `(15 - 8)/(17)`
sinA - cosA = `(7)/(17)`.
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