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Question
If log 3 m = x and log 3 n = y, write down
`3^(1-2y+3x)` in terms of m an n
Solution
`3^(1-2y+3x)` in terms of m an n
log 3 m = x
⇒ m = 3x
log 3 n = y
⇒ n = 3y
∴ `3^(1-2y+3x)`
= 3.3-2y.33x
= 3.(3y)-2.(3x)3
= 3n-2.m3
= `(3"m"^3)/"n"^2`.
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