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Question
If `p/q = r/s`, prove that `(2p + 3q)/(2p - 3q) = (2r + 3s)/(2r - 3s)`.
Solution
We have
`p/q = r/s` ...[Multiplying both side by 2 / 3]
`(2p)/(3q) = (2r)/(3s)` ...[By componendo and dividendo]
∴ `(2p + 3q)/(2p - 3q) = (2r + 3s)/(2r - 3s)`.
Hence proved.
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