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If X^2 + 1/X^2 = 66 Find the Value of X - 1/X - Mathematics

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Question

If `x^2 + 1/x^2 = 66`, find the value of `x - 1/x`

Solution

`(x - 1/x)^2 = x^2 = 1/x^2 - 2 xx  x xx 1/x`

`(x - 1/x)^2 = x^2 + 1/x^2 - 2`

`=>(x - 1/x)^2 = 66 - 2`    [∵ `x^2 + 1/x^2 = 66`]

`=> (x  - 1/x)^2 = 64`

`=> (x - 1/x)^2 = (+-8)^2`

`=> x - 1/x = +-8^2`

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Chapter 4: Algebraic Identities - Exercise 4.1 [Page 7]

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RD Sharma Mathematics [English] Class 9
Chapter 4 Algebraic Identities
Exercise 4.1 | Q 11 | Page 7

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