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Question
In ∆ABC, ray AD bisects ∠A and intersects BC in D. If BC = a, AC = b and AC = c, prove that \[DC = \frac{ab}{b + c}\]
Solution
Since BC = CD + BD
`⇒ CD =BC -BD`
`CD = a - (ac)/(b+c)`
`= (ab)/(b+c)`
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