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Question
In the below fig, p is a transversal to lines m and n,`∠`2 = 120° and `a∠`5 = 60°. Prove that m || n.
Solution
Given that
`∠`2 = 120°, `∠`5 = 60°
To prove
`∠`2 + `∠`1 = 180° [ ∵ Linear pair]
120° + `∠`1 = 180°
`∠`1 = 180° -120°
`∠`1 = 60°
Since `∠`1 = `∠`5 = 60°
∴ m || n [As pair of corresponding angles are equal]
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