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In the Following Figure, Seg Be ⊥ Seg Ab and Seg Ba ⊥ Seg Ad. If Be = 6 and a D = 9 F I N D a ( δ a B E ) a ( δ B a D ) ⋅ - Geometry Mathematics 2

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Question

In the following figure, seg BE ⊥ seg AB and seg BA ⊥ seg AD. If BE = 6 and \[\text{AD} = 9 \text{ find} \frac{A\left( \Delta ABE \right)}{A\left( \Delta BAD \right)} \cdot\]

Sum

Solution

\[AD = 9 \text{ find} \frac{A\left( \Delta ABE \right)}{A\left( \Delta BAD \right)} \cdot\]

\[\frac{Ar\left( \bigtriangleup ABE \right)}{Ar\left( \bigtriangleup BAD \right)} = \frac{\frac{1}{2} \times BE \times AB}{\frac{1}{2} \times AB \times AD} = \frac{BE}{AD} = \frac{6}{9} = \frac{2}{3}\]
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