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Question
In Δ PQR, MN is drawn parallel to QR. If PM = x, MQ = (x-2), PN = (x+2) and NR = (x-1), find the value of x.
Solution
In Δ PQR , MN || QR ,
∴ By BPT `"PM"/"MQ" = "PN"/"NR"`
`"x"/("x" - 2) = ("x" + 2)/("x" - 2)`
⇒ x2 - x = x2 - 4
⇒ - x = - 4
⇒ x = 4
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