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Question
Select the appropriate alternative.
In ∆ABC and ∆PQR, in a one to one correspondence \[\frac{AB}{QR} = \frac{BC}{PR} = \frac{CA}{PQ}\]
Options
∆PQR ~ ∆ABC
∆PQR ~ ∆CAB
∆CBA ~ ∆PQR
∆BCA ~ ∆PQR
Solution
\[\frac{AB}{QR} = \frac{BC}{PR} = \frac{CA}{PQ}\]
By SSS test of similarity
∆PQR ~ ∆CAB
Hence, the correct option is ∆PQR ~ ∆CAB.
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