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Question
Δ ABC - Δ XYZ. If area of Δ ABC is 9cm2 and area of Δ XYZ is 16cm2 and if BC= 2.1cm, find the length of YZ.
Solution
Given : Δ ABC ∼ Δ XYZ
To find : YZ
Sol : `("Ar" triangle "ABC")/("Ar" triangle "XYZ") = ("BC"^2)/("YZ"^2)`
[The ration of areas of two similar triangle is equal to the ratio of square of their corresponding sides.]
`9/16 = (2.1)^2/"YZ"^2`
Taking square root both sides ,
`3/4 = 2.1/"YZ"`
YZ = `(2.1 xx 4)/3`
YZ = 2.8 cm
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