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In the Given Figure, Abcd is a Rectangle with Ab = 80 Cm and Bc = 70 Cm, ∠Aed = 90° and De = 42 Cm. a Semicircle is Drawn, Taking Bc as Diameter. Find the Area of the Shaded Region. - Mathematics

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Question

In the given figure, ABCD is a rectangle with AB = 80 cm and BC = 70 cm, ∠AED = 90° and DE = 42 cm. A semicircle is drawn, taking BC as diameter. Find the area of the shaded region.

Sum

Solution

We know that the opposite sides of a rectangle are equal

AD = BC =  70 cm

In right triangle AED

AE2 = AD2 − DE2  
= (70)2 − (42)2 
= 4900 − 1764

= 3136
∴ AE2 = 3136
⇒ AE = 56
= Area of the shaded region = Area of rectangle − (Area of triangle  AED + Area of semicircle)

`= "AB"xx"BC"-[1/2xx"AE"xx"DE" + 1/2pi("BC"/2)^2]`

`= 80xx70-[1/2xx56xx42+1/2xx22/7(70/2)^2]`

= 5600 - 3101

= 2499 cm2

Hence, the area of shaded region is 2499 cm2

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Chapter 18: Area of Circle, Sector and Segment - Exercise 18A [Page 834]

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RS Aggarwal Mathematics [English] Class 10
Chapter 18 Area of Circle, Sector and Segment
Exercise 18A | Q 44 | Page 834

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