Question

In the given figure, ABCD is a square of side 7 cm, DPBA and DQBC are quadrants of circles each of the radius 7 cm. Find the area of shaded region.

Answer 1

Area of the shaded portion = (Area of quadrant DPBA + Area of quadrant DQBC) − Area of Square ABCD

${\displaystyle =[\frac{1}{4}\pi {\left(7\right)}^2+\frac{1}{4}\pi {\left(7\right)}^2]-{\left(7\right)}^2}$

${\displaystyle =\frac{1}{2}\times \frac{22}{7}{\left(7\right)}^2-49}$

= 28 cm² 

Hence, the area of the shaded portion is 28 cm².