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Question
A sector of 56° cut out from a circle contains area of 4.4 cm2. Find the radius of the circle
Solution
Angle subtended by sector at centre 𝜃 = 56°
Let radius be ‘x’ cm
Area of sector =`theta/360^@× pir^2`
=`56/360×22/7× r^2`
=`22/45`𝑟2
But area of sector = 4.4cm2 =`44/10cm^2`
`22/45r^2 =44/10`
⇒ `r^2 =(45×44)/(22×10)`= 9
⇒ 𝑟 = `sqrt(9)`
= 3 𝑐𝑚
∴ radius (r) = 3cm
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