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A Sector of 56° Cut Out from a Circle Contains Area of 4.4 Cm2. Find the Radius of the Circle - Mathematics

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प्रश्न

A sector of 56° cut out from a circle contains area of 4.4 cm2. Find the radius of the circle

उत्तर

Angle subtended by sector at centre 𝜃 = 56°

Let radius be ‘x’ cm

Area of sector =`theta/360^@× pir^2`

=`56/360×22/7× r^2`

=`22/45`𝑟2

But area of sector = 4.4cm2 =`44/10cm^2`

`22/45r^2 =44/10`

⇒ `r^2 =(45×44)/(22×10)`= 9

⇒ 𝑟 = `sqrt(9)`

= 3 𝑐𝑚

∴ radius (r) = 3cm

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अध्याय 13: Areas Related to Circles - Exercise 13.2 [पृष्ठ २५]

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आरडी शर्मा Mathematics [English] Class 10
अध्याय 13 Areas Related to Circles
Exercise 13.2 | Q 17 | पृष्ठ २५

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