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Question
A chord of a circle of radius 10 cm subtends a right angle at the centre. Find the area of the corresponding:
Major sector [Use π = 3.14]
Solution
Area of sector = `theta/(360°) xxpir^2`
`= (90°)/(360°) xx 314 /100 xx 10 xx 10`cm2
= `1/4 xx 314 ` cm2
`= 157/2` cm2
= 78.5 cm2
Area of the major sector = [Area of the circle] - [Area of the sector]
= `pir^2 - 78.5 "cm"^2`
`= [314/100 xx 10xx10 - 78.5]`cm2
= [314 − 78.5]cm2
= 235.5 cm2
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