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Question
In how many ways can the letters of the word PERMUTATIONS be arranged if the words start with P and end with S.
Solution
The word PERMUTATIONS has a total 12 letters, in which T – 2, rest all are different.
The positions of P and S have been fixed.
Hence, in this case, required number of arrangements
= `(10!)/(2!)` = 1814400.
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