Advertisements
Advertisements
Question
In a quadrilateral ABCD, the angles A, B, C and D are in the ratio 1 : 2 : 4 : 5. Find the measure of each angles of the quadrilateral
Solution
Let the angles of the quadrilateral be
A = x, B = 2x, C = 4x and D = 5x then,
A + B + C + D = 360°
⇒ x + 2x + 4x + 5x = 360°
⇒ 12x = 360°
⇒ x = `(360°)/12`
⇒ x = 30°
∴ A = x = 30°
B = 2x = 60°
C = 4x = 30° (4) = 120°
D = 5x = 5 (30°) = 150°
APPEARS IN
RELATED QUESTIONS
Find x in the following figure:
In a quadrilateral ABCD, CO and DO are the bisectors of `∠`C and ∠D respectively. Prove that
`∠`COD = `1/2` (`∠`A+ `∠`B).
Two opposite angles of a parallelogram are (3x – 2)° and (50 – x)°. Find the measure of each angle of the parallelogram .
In a quadrilateral ABCD, bisectors of angles A and B intersect at O such that ∠AOB = 75°, then write the value of ∠C + ∠D.
The two diagonals are equal in a
In a rhombus ABCD, if ∠ACB = 40°, then ∠ADB =
All the angles of a quadrilateral are equal. What special name is given to this quadrilateral?
Can all the angles of a quadrilateral be right angles? Give reason for your answer.
The polygon in which sum of all exterior angles is equal to the sum of interior angles is called ______.
Three angles of a quadrilateral are equal. Fourth angle is of measure 120°. What is the measure of equal angles?
