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Question
In the figure, BC = CE and ∠1 = ∠2. Prove that ΔGCB ≅ ΔDCE.
Solution
In ΔGCB and ΔDCE and
∠1 + ∠GBC = ∠2 + ∠DEC = 180°
∠1 = ∠2 =
⇒ ∠GBC = ∠DEC
BC = CE
∠GCB = ∠DCE = ...(vertically opposite angles)
Therefore,
ΔGCB ≅ ΔDCE ....(ASA criteria).
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