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Question
In the following figure, PQ is the tangent to the circle at A, DB is a diameter and O is the centre of the circle. If ∠ ADB = 30° and ∠ CBD = 60° ; calculate ∠ PAD.
Solution
OA = OD (radii of the same circle)
∴ ∠ OAD = ∠ ODA = 30°
But, OA ⊥ PQ
∴ ∠ PAD = ∠ OAP - ∠ OAD = 90° - 30° = 60°
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