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Question
PA and PB are tangents from P to the circle with centre O. At M, a tangent is drawn cutting PA at K and PB at N. Prove that KN = AK + BN.
Solution
KA = KM ---(1) {Length of tangents drawn from an external point to a circle are equal }
NM = NB
KN = KM + MN
KN = KA+ BM {Using (1)}
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