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Question
In the given figure, diameter AB and chord CD of a circle meet at P. PT is a tangent to the circle at T. CD = 7.8 cm, PD = 5 cm, PB = 4 cm. Find the length of tangent PT.
Solution
Since PT2 = PC × PD
⇒ PT2 = 12.8 × 5
⇒ PT2 = 64
⇒ PT2 = 8 cm
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