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Question
At one end A of a diameter AB of a circle of radius 5 cm, tangent XAY is drawn to the circle. The length of the chord CD parallel to XY and at a distance 8 cm from A is ______
Options
4 cm
5 cm
6 cm
8 cm
Solution
At one end A of a diameter AB of a circle of radius 5 cm, tangent XAY is drawn to the circle. The length of the chord CD parallel to XY and at a distance 8 cm from A is 8 cm.
Explanation:
First, draw a circle of radius 5 cm with centre O.
A tangent XY is drawn at point A.
A chord CD is drawn which is parallel to XY and at a distance of 8 cm from A.
Now, ∠OAY = 90° ...[∵ Tangent at any point of circle is perpendicular to the radius through the point of contact]
∠OAY + ∠OED = 180° ...[∵ Sum of cointerior angles is 180°]
⇒ ∠OED = 180° – 90° = 90°
Also, AE = 8 cm.
Join OC
OC = 5 cm ...[Radius of circle]
OE = AE – OA
= 8 – 5
= 3 cm
Now, in right angled ∆OEC,
OC2 = OE2 + EC2 ...[By Pythagoras theorem]
⇒ EC2 = OC2 – OE2
⇒ EC2 = 52 – 32
⇒ EC2 = 25 – 9 = 16
⇒ EC = 4 cm
Since, perpendicular from centre to the chord bisects the chord.
∴ CE = ED
⇒ CD = 2 × EC
⇒ CD = 2 × 4
⇒ CD = 8 cm
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