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Question
In the given figure, ∠A = 64°, ∠ABC = 58°. If BO and CO are the bisectors of ∠ABC and ∠ACB respectively of ΔABC, find x° and y°
Solution
In the given ΔABC
∠A = 64° and ∠B = 58°
∠C = 180° − (64° + 58°)
= 180° – 122°
= 58°
Since OC is the bisector of ∠C
y = `(58^circ)/2`
= 29°
Given ΔOBC
∠OCB = `(58^circ)/2` = 29°
∠OCB = 29°
∴ ∠BOC = 180° − (29° + 29°)
x = 180° – 58°
x = 122°
∠x = 122° and ∠y = 29°.
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