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Question
In the matrix A = `[("a", 1, x),(2, sqrt(3), x^2 - y),(0, 5, (-2)/5)]`, write: elements a23, a31, a12
Solution
We have, A = `[("a", 1, x),(2, sqrt(3), x^2 - y),(0, 5, (-2)/5)]`
Since, aij is the element lying in the ith row an jth column
We have a23 = x2 – y, a31 = 0, a12 = 1.
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