Advertisements
Advertisements
Question
Is it possible to have a regular polygon whose exterior angle is: 100°
Solution
Let no. of. sides = n
Each exterior angle = 100°
= `360^circ/"n" = 100^circ`
∴ n = `360^circ/100^circ`
n = `18/5`
Which is not a whole number.
Hence, it is not possible to have a regular polygon whose each exterior angle is 100°.
APPEARS IN
RELATED QUESTIONS
Fill in the blanks :
In case of regular polygon, with :
No.of.sides | Each exterior angle | Each interior angle |
(i) ___8___ | _______ | ______ |
(ii) ___12____ | _______ | ______ |
(iii) _________ | _____72°_____ | ______ |
(iv) _________ | _____45°_____ | ______ |
(v) _________ | __________ | _____150°_____ |
(vi) ________ | __________ | ______140°____ |
Is it possible to have a regular polygon whose each exterior angle is: 80°
Find the number of sides in a regular polygon, if its interior angle is equal to its exterior angle.
The exterior angle of a regular polygon is one-third of its interior angle. Find the number of sides in the polygon.
The sum of interior angles of a regular polygon is twice the sum of its exterior angles. Find the number of sides of the polygon.
Three of the exterior angles of a hexagon are 40°, 51 ° and 86°. If each of the remaining exterior angles is x°, find the value of x.
The ratio between the number of sides of two regular polygons is 3 : 4 and the ratio between the sum of their interior angles is 2 : 3. Find the number of sides in each polygon.
Calculate the number of sides of a regular polygon, if: its interior angle is five times its exterior angle.
The sum of interior angles of a regular polygon is thrice the sum of its exterior angles. Find the number of sides in the polygon.
Find a number of side in a regular polygon, if it exterior angle is: 30°.