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Question
Let A = `[[2,4],[3,2]]`, `B=[[1,3],[-2,5]]`and `c =[[-2,5],[3,4]]`.Find each of the following: 2A − 3B
Solution
2A−3B
⇒ 2A - 3B =` 2[[2 4],[3 2 ]]`-3`[[1 3],[-2 5]]`
⇒ 2A−3B=`[[4 8],[6 4]]-[[1 3],[-2 5]]`
⇒ 2A−3B= `[[4 8],[6 4]]-[[3 9],[-6 15]]`
⇒ 2A−3B=`[[4 -3 8-9],[6+6 4-15]]`
⇒ 2A−3B=`[[1 -1],[12 -11]]`
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